Carilah himpunan penyelesaian dari: 1.x+8=2(y+3) dan x-4y=4(x-2y+2) 2.5{x-(y+1)}=3x+2(3y-1)+20 dan 2{2x-3(2y-1)}=-5x+y

x+8=2(y+3)
x+8=2y+6
x-2y= - 2 ...(1)
x-4y=4(x-2y+2)
x-4y=4x-8y+8
x-4x-4y+8y=8
-3x+4y=8 ... (2)
eliminasi 1 dan 2
x-2y=-2    (x2) --> 2x-4y=-4
-3x+4y=8 (x1) --> -3x+4y=8 +
                               -x=4 --> x=-4
substitusi
x-2y=-2
-4-2y=-2
-2y=-2+4
y=2/-2
y=-1
Hp={(-4,-1)}


5{x-(y+1)}=3x+2(3y-1)+20
5{x-y-1}=3x+6y-2+20
5x-5y-5=3x+6y+18
5x-3x-5y-6y=18+5
2x-11y=23 ...(1)
2{2x-3(2y-1)}=-5x+y
2{2x-6y+3}=-5x+y
4x-12y+6=-5x+y
4x+5x-12y-y=-6
9x-12y=-6 ...(2)
eliminsi 1 dan 2
2x-11y=23 (x12) --> 24x-132y=276
9x-12y=-6 (x11)--> 99x-132y=-66 _
                               -75x=342 --> x=342/-75 = -114/25
substitusi
2x-11y=23
2(-114/25)-11y=23
-11y=23+228/25
-11y = (575+228)/25
-11y = 803/25
y= 803/25 x - 1/11
y=-73/25
HP={(-114/25, -73/25)}