2x+3y=12 x+2y=10 menggunakan metode substitusi?

2x + 3y = 12      x1
x + 2y = 10        x2
-----------------------------
2x + 3y = 12
2x + 4y = 20
------------------------ dikurang
-y = -8
y = 8

2x + 3(8) = 12
2x + 24 = 12
2x = -12
x = -6

2x+3y=12
x+2y=10 --> x=10-2y

2(10-2y) + 3y = 12
20 - 4y + 3y =12
20 - y = 12
-y = -8
 y= 8

x+2y=10
x + 2(8) = 10
x + 16 = 10
x = -6