supaya persamaan tersebut benar maka x=?

Mapel : Matematika Wajib (Kelas X SMA)
Materi : Matriks
Indikator : Mencari HP dalam suatu persamaan matriks

Langkah Penyelesaian dan Jawaban :
AX = B, maka
X = A⁻¹B

[tex]A^{-1} = \frac{1}{5 - 6} \left[\begin{array}{ccc}5&- 2\\-3&1\end{array}\right] \\ \\ A^{- 1} = - 1 \left[\begin{array}{ccc}5&- 2\\-3&1\end{array}\right] \\ \\ A^{- 1} = \left[\begin{array}{ccc}- 5&2\\3&-1\end{array}\right] \\ \\ x = \left[\begin{array}{ccc}- 5&2\\3&-1\end{array}\right] \left[\begin{array}{ccc}- 2&5\\-4&13\end{array}\right] \\ \\ x = \left[\begin{array}{ccc}10 - 8&- 25 + 26\\- 6 + 4&15 - 13\end{array}\right] \\ \\ x = \left[\begin{array}{ccc}2&1\\-2&2\end{array}\right][/tex]