tlng bantuannya mbak dan mas bro

3u-2y+z=2. x1
u- 3y+2z=1. x3

3u-2y+z=2
3u-3y+6z= 3 eliminasi

y-5z=-1. pers 3

u-3y+2z=1 x2
2u+2y-3z=-5 x1

2u-3y+2z=2
2u+2y-3z=-5 eliminasi pers

-5y+5z=7 pers 4

y-5z=-1
-5y+5z=7 eliminasi pers

-4 y= -8
y= 2
sybstitusi
2u+3y-z=-5
2u+6-z=-5
2u-z=-11

substitusi pers
u-3y+2z=1
u-6+2z=1
u+6z=7
eliminasi kedu pers
2u-z=-11 x1
u+6z= 7 x2
2u -z= -11
2u+ 12z= 14