1. Sin 2x=1/2, 0≤x≤2π 2. Cos(x+10°)=-1, 0≤x≤360° 3. 2sin 2x+1=0, 0≤x≤π Mohon bantuan kakak
Matematika
AdePRY
Pertanyaan
1. Sin 2x=1/2, 0≤x≤2π
2. Cos(x+10°)=-1, 0≤x≤360°
3. 2sin 2x+1=0, 0≤x≤π
Mohon bantuan kakak
2. Cos(x+10°)=-1, 0≤x≤360°
3. 2sin 2x+1=0, 0≤x≤π
Mohon bantuan kakak
1 Jawaban
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1. Jawaban dyahsandra1822
yg no 3 x nya tdk memiliki penyelesaian.
1. sin 2x=1/2
sin2x=sin30 derajat
penyelesaian
# 2x=30+n.360
x=15+n.18
n=0 -> x= 15+0.180= 15 derajat
n=1 -> x= 15++1.180=165
# 2x=(180-30)+n.360
2x= 150+n.360
x= 75+n.180
n= 0 => x= 75+ 0.180 =75
n= 1 => x= 75 +1.180 =255
jadi x = 15,75,165,225
2. cos(x+10) = -1
cos(x+10) = cos 180
peyelesaian
# x+10= 180+n.360
x= 170 +n.360
n=0 => x= 170 +0.360=170
# x+10= -180+n.360
x= -190 +n.360
n=1 => x= -190 +1.360=170
jadi x = 170