3+10+17+24+..tentukan Jumlah 10 suku

S10 = 5 ( 6 + 9×7 )
= 5 ( 6 + 63 )
= 5 × 69
= 345

Sn = n/2(2a+(n-1)b)
S10 = 10/2[2(3)+(10-1)7]
S10 = 5(6+9×7)
S10 = 5(6+63)
S10 = 5 × 69
S10 = 345