mohon dibantu jawab ya kak

 [tex] \frac{8}{3a+6} x \frac{a+2}{4}= \frac{8}{3(a+2)} x \frac{a+2}{4} = \frac{2}{3} [/tex]

[tex] \frac{6}{ a^{2} +4a} x \frac{a}{12} = \frac{6}{a(a+4)} x \frac{a}{12} = \frac{1}{2a+8} [/tex]