Matematika

Pertanyaan

tolong yang jago matematika nomer 15 sampai 18
tolong yang jago matematika nomer 15 sampai 18

2 Jawaban

  • Persamaan Bentuk Pecahan
    ..
    (di lampiran)

    Gambar lampiran jawaban DB45
  • 15)
    [1/(x^2 + 4x + 3)] + [1/(x + 3)]
    = [1/(x + 3)(x + 1)] + [(x + 1)/(x + 3)(x + 1)]
    = [1 + x + 1]/(x + 3)(x + 1)
    = (x + 2)/(x + 3)(x + 1)
    = (x + 2)/(x^2 + 4x + 3)

    16)
    [1/(a^2 + 2a + 1)] + [1/(a + 1)]
    = [1/(a + 1)(a + 1)] + [(a + 1)/(a + 1)(a + 1)]
    = (1 + a + 1)/(a + 1)(a + 1)
    = (a + 2)/(a + 1)(a + 1)
    = (a + 2)/(a + 1)^2
    = (a + 2)/(a^2 + 2a + 1)

    17)
    [1/(a^2 + 2a + 1)] + [1/(a^2 - 1)]
    = [1/(a + 1)(a + 1)] + [1/(a - 1)(a + 1)]
    = [(a - 1)/(a - 1)(a + 1)(a + 1)] + [(a + 1)/(a - 1)(a + 1)(a + 1)]
    = [a - 1 + a + 1]/[(a - 1)(a + 1)(a + 1)]
    = (2a)/(a - 1)(a + 1)(a + 1)
    = (2a)/(a - 1)(a + 1)^2
    = (2a)/(a^3 + a^2 - a - 1)

    18)
    [(x + 4)/(x^2 - 9)] - [1/(x - 3)]
    = [(x + 4)/(x - 3)(x + 3)] - [(x + 3)/(x - 3)(x + 3)]
    = [x + 4 - (x + 3)]/(x - 3)(x + 3)
    = (x + 4 - x - 3)/(x - 3)(x + 3)
    = 1/(x - 3)(x + 3)
    = 1/(x^2 - 9)