tolong yang jago matematika nomer 4 dan nomer 5

no. 4
[tex] \frac{ x^{2} +2x+1}{x} : \frac{ x^{2} -x-2}{x} = \frac{ x^{2} +2x+1}{x} x \frac{x}{ x^{2} -x-2} = \frac{ x^{2} +2x+1}{ x^{2} -x-2} = \frac{(x + 1)(x + 1)}{(x - 2)(x + 1)} = \frac{x + 1}{x - 2} [/tex]


no. 5
[tex] \frac{2a+2}{a} : \frac{a + a^{2} }{4} = \frac{2a+2}{a} x \frac{4}{a + a^{2} } = \frac{2(a+1)}{a} x \frac{4}{a(1 + a)} = \frac{8}{ a^{2} } [/tex]

4)
(x^2 + 2x + 1)/x : (x^2 - x - 2)/x
= [((x + 1)(x + 1))/x] × [x/(x - 2)(x + 1)]
= [(x + 1)(x + 1)] / [(x - 2)(x + 1)]
= (x + 1)/(x - 2)

5)
(2a + 2)/a : (a + a^2)/4
= [(2a + 2)/a] × [4/(a + a^2)]
= [4 × (2a + 2)]/[a(a + a^2)]
= (8a + 8)/(a^2 + a^3)
= [8(a + 1)]/[a^2(1 + a)]
= 8/a^2

6]
[(12x + 144)/(5x - 15)] : (x + 12)
= [(12x + 144)/(5x - 15)] × [1/(x + 12)]
= (12x + 144)/[(5x - 15)(x + 12)]
= [12(x + 12)]/[(5x - 15)(x + 12)]
= 12/(5x - 15)